WBJEE · Physics · Electrostatics
A thin glass rod is bent in a semicircle of radius \(\mathrm{R}\). A change is non-uniformly distributed along the rod with a linear charge density \(\lambda=\lambda_0 \sin \left(\lambda_0\right.\) is a positive constant). The electric field at the centre \(P\) of the semicircle is,

- A \(-\frac{\lambda_0}{8 \pi \varepsilon_0 R} \hat{j}\)
- B \(\frac{\lambda_0}{8 \pi \varepsilon_0 R} \hat{j}\)
- C \(\frac{\lambda_0}{8 \pi \varepsilon_0 R} \hat{i}\)
- D None of these
Answer & Solution
Correct Answer
(D) None of these
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