WBJEE · Chemistry · Biomolecules
In aqueous solution glucose remains as
- A Only in open chain form
- B Only in pyranoze form
- C Only in furanose forms
- D In all three forms in equilibrium
Answer & Solution
Correct Answer
(D) In all three forms in equilibrium
Step-by-step Solution
Detailed explanation
Hints: \(\begin{aligned} & \beta-\mathrm{D}-\text { glucose } \rightleftharpoons \mathrm{D}-\text { glucose } \rightleftharpoons \alpha-\mathrm{D}-\text { glucose } \\ & (\approx 64 \%) \quad\qquad(\text {open chain } \approx 0.02 \%) \qquad~~(\approx 34 \%)\end{aligned}\)
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