WBJEE · Physics · Ray Optics
A point object is placed on the axis of a thin convex lens of focal length \(0.05 \mathrm{m}\) at a distance of \(0.2 \mathrm{m}\) from the lens and its image is formed on the axis. If the object is now made to oscillate along the axis with a small amplitude of \(A \mathrm{cm},\) then what is the amplitude of oscillation of the image? \(\left[\right.\) you may assume, \(\frac{1}{1+x} \approx 1-x,\) where \(\left.x< < 1\right]\)
- A \(\frac{4 A}{9} \times 10^{-2} m\)
- B \(\frac{5 A}{9} \times 10^{-2} m\)
- C \(\frac{A}{3} \times 10^{-2} m\)
- D \(\frac{A}{9} \times 10^{-2} \mathrm{m}\)
Answer & Solution
Correct Answer
(D) \(\frac{A}{9} \times 10^{-2} \mathrm{m}\)
Step-by-step Solution
Detailed explanation
According to the question, we can draw the following diagram Given, \(u=-0.2 \mathrm{m}\) and \(f=0.05 \mathrm{m}\) As we know that,…
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