WBJEE · Maths · Straight Lines
If \(4 a^2+9 b^2-c^2+12 a b=0\), then the family of straight lines \(a x+b y+c=0\) is concurrent at
- A \((2,3)\) or \((-2,-3)\)
- B \((-2,3)\) or \((2,3)\)
- C \((3,2)\) or \((-3,2)\)
- D \((-3,2)\) or \((2,3)\)
Answer & Solution
Correct Answer
(A) \((2,3)\) or \((-2,-3)\)
Step-by-step Solution
Detailed explanation
Hint : \(\because 2 a+3 b-c=0\) or \(2 a+3 b+c=0\)…
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