WBJEE · Maths · Differential Equations
The differential equation representing the family of curves \(y^{2}=2 d(x+\sqrt{d})\) where \(d\) is a parameter, is of
- A order 2
- B degree 2
- C degree 3
- D degree 4
Answer & Solution
Correct Answer
(C) degree 3
Step-by-step Solution
Detailed explanation
Given, \(\quad y^{2}=2 d(x+\sqrt{d})\) \(\Rightarrow\) 2y \(y_{1}=2 d \Rightarrow d=y y_{1}\) From Eq. (i), \[ y^{2}=2 y y_{1}\left(x+\sqrt{y y_{1}}\right) \] \(\Rightarrow \quad y^{2}-2 y y_{1} x=\sqrt{y y_{1}} \cdot 2 y y_{1}\)…
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