WBJEE · Maths · Trigonometric Equations
If \(\frac{1}{6} \sin \theta, \cos \theta, \tan \theta\) are in G.P., then the solution set of \(\theta\) is
- A \(2 \mathrm{n} \pi \pm \frac{\pi}{6}\)
- B \(2 \mathrm{n} \pi \pm \frac{\pi}{3}\)
- C \(\mathrm{n} \pi+(-1)^{\mathrm{n}} \frac{\pi}{3}\)
- D \(\mathrm{n} \pi+\frac{\pi}{3}\)
Answer & Solution
Correct Answer
(B) \(2 \mathrm{n} \pi \pm \frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text {Hint : } 6 \cos ^3 \theta+\cos ^2 \theta-1=0 \\ & \Rightarrow \quad(2 \cos \theta-1)\left(3 \cos ^2 \theta+2 \cos \theta+1\right)=0 \\ & \Rightarrow \quad \cos \theta=\frac{1}{2}\left(3 \cos ^2 \theta+2 \cos \theta+1 \neq 0\right) \end{aligned}\)
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