WBJEE · Maths · Complex Number
The value of \(\left(\frac{1+\sqrt{3} i}{1-\sqrt{3 i}}\right)^{64}+\left(\frac{1-\sqrt{3} i}{1+\sqrt{3} i}\right)^{64}\) is
- A 0
- B -1
- C 1
- D \(i\)
Answer & Solution
Correct Answer
(B) -1
Step-by-step Solution
Detailed explanation
We know that, \(\omega=\frac{-1+\sqrt{3} i}{2} 1-\sqrt{3} i=-2 \omega\) and \(\omega^{2}=\frac{-1-\sqrt{3} i}{2} 1+\sqrt{3} i=-2 \omega^{2}\) Now,…
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