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WBJEE · Maths · Functions

The total number of injections (one-one into mappings) from \(\quad\left\{a_{1}, a_{2}, a_{3}, a_{4}\right\}\)
\(\left(b_{1}, b_{2}, b_{3}, b_{4}, b_{5}, b_{6}, b_{7}\right)\) is

  1. A 400
  2. B 420
  3. C 800
  4. D 840
Verified Solution

Answer & Solution

Correct Answer

(D) 840

Step-by-step Solution

Detailed explanation

Let \(A=\left\{a_{1}, a_{2}, a_{3}, a_{4}\right\}\) \(\begin{aligned} B &=\left\{b_{1}, b_{2}, b_{3}, b_{4}, b_{5}, b_{6}, b_{7}\right\} \\ n(A) &=4, n(B)=7 \end{aligned}\) The total number of infections \(={ }^{7} P_{4}\) \(=\frac{71}{3 !}=7 \cdot 6 \cdot 5 \cdot 4=840\)