WBJEE · Maths · Continuity and Differentiability
\(f(x)=\left\{\begin{array}{cc}{[x]+[-x],} & \text { when } x \neq 2 \\ \lambda & \text { when } x=2\end{array}\right.\)
If \(f(x)\) is continuous at \(x=2\), the value of \(\lambda\) will be
- A -1
- B 1
- C 0
- D 2
Answer & Solution
Correct Answer
(A) -1
Step-by-step Solution
Detailed explanation
Hints: \(\mathrm{LHL}=\operatorname{Lt}_{\mathrm{h} \rightarrow 0}[2-\mathrm{h}]+[-(2-\mathrm{h})]\) \(=\operatorname{Lt}_{\mathrm{h} \rightarrow 0} 1+(-2+\mathrm{h})=1-2=-1\)…
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