WBJEE · Maths · Circle
For the two circles \(x^2+y^2=16\) and \(x^2+y^2-2 y=0\) there is / are
- A one pair of common tangents
- B only one common tangent
- C three common tangents
- D no common tangent
Answer & Solution
Correct Answer
(D) no common tangent
Step-by-step Solution
Detailed explanation
Hints: \[ \begin{array}{ll} \mathrm{C}_2(0,0) & r_1=4 \\ \mathrm{C}_2(0,1) & r_2=\sqrt{0+1}=1 \end{array} \] \[ \begin{aligned} & \mathrm{C}_1 \mathrm{C}_2=\sqrt{0+1}=1 \\ & r_1-r_2=3 \\ & \mathrm{C}_1 \mathrm{C}_2 < r_1-r_2 \end{aligned} \]
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