WBJEE · Chemistry · States of Matter
Two gases \(X\) (molecular weight \(M_{X}\) ) and Y (molecular weight \(M_{Y} ; M_{Y}>M_{X}\) ) are at the same temperature \(T\) in two different containers. Their root mean square velocities are \(C_{X}\) and \(C_{Y}\) respectively. If the average kinetic energies per molecule of two gases \(X\) and \(Y\) are \(E_{x}\) and \(E_{Y}\) respectively then which of the following relation(s) is(are) true?
- A \(E_{X}>E_{Y}\)
- B \(C_{X}>C_{Y}\)
- C \(E_{X}=E_{Y}=(3 / 2) R T\)
- D \(E_{X}=E_{Y}=(3 / 2) k_{B} T\)
Answer & Solution
Correct Answer
(D) \(E_{X}=E_{Y}=(3 / 2) k_{B} T\)
Step-by-step Solution
Detailed explanation
Given, molecular weight of \(X=M_{X}\) Mol. wt. of \(Y=M_{Y}\) and \(M_{Y}>M_{x}\) Root mean square velocitios \(=C_{X}\) and \(C_{Y}\) respectively Average \(\mathrm{KE}\)/molecule \(=E_{X}\) and \(E_{Y}\) respectively We know that. Root mean square velocity.…
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