WBJEE · Maths · Straight Lines
The equation of the locus of the point of intersection of the straight lines \(x \sin \theta+(1-\cos \theta) y=a \sin \theta\) and \(x\) sin \(\theta-(1+\) \(\cos \theta) y+a \sin \theta=0\) is
- A \(y \pm a x\)
- B \(x= \pm\) ay
- C \(y^2=4 x\)
- D \(x^2+y^2=a^2\)
Answer & Solution
Correct Answer
(D) \(x^2+y^2=a^2\)
Step-by-step Solution
Detailed explanation
Hints: \(y=a \sin \theta\) \(x=a \cos \theta \text {. }\) \(x^2+y^2=a^2\)
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