WBJEE · Maths · Ellipse
The points of intersection of two ellipses \(x^{2}+2 y^{2}-6 x-12 y+20=0\) and \(2 x^{2}+y^{2}-10 x-6 y+15=0\) lie on a circle. The centre of the circle is
- A \((8,3)\)
- B \((8,1)\)
- C \(\left(\frac{8}{3}, 3\right)\)
- D \((3,8)\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{8}{3}, 3\right)\)
Step-by-step Solution
Detailed explanation
\(x^{2}+2 y^{2}-6 x-12 y+20+\lambda\left(2 x^{2}+y^{2}-10 x-6 y+15\right)=0\)…
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