WBJEE · Chemistry · s Block Elements
\(\mathrm{Na}_2 \mathrm{CO}_3\) is prepared by Solvay process but \(\mathrm{K}_2 \mathrm{CO}_3\) cannot be prepared by the same because
- A \(\mathrm{K}_2 \mathrm{CO}_3\) is highly soluble in \(\mathrm{H}_2 \mathrm{O}\)
- B \(\mathrm{KHCO}_3\) is sparingly soluble
- C \(\mathrm{KHCO}_3\) is appreciably soluble
- D \(\mathrm{KHCO}_3\) decomposes
Answer & Solution
Correct Answer
(C) \(\mathrm{KHCO}_3\) is appreciably soluble
Step-by-step Solution
Detailed explanation
Hint: \(\left(\mathrm{NH}_4\right) \mathrm{HCO}_3+\mathrm{KCl} \longrightarrow \mathrm{KHCO}_3(\mathrm{aq})+\mathrm{NH}_4 \mathrm{Cl}(\mathrm{aq})\) \(\mathrm{KHCO}_3\) being appreciably soluble cant be isolated from reaction medium easily.
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