WBJEE · Maths · Straight Lines
The line parallel to the \(x\)-axis passing through the intersection of the lines \(a x+2 b y+3 b=0\) and \(b x-2 a y-3 a=\) where \((a, b) \neq(0,0)\) is
- A above \(x\)-axis at a distance \(\frac{3}{2}\) from it
- B above x -axis at a distance \(\frac{2}{3}\) from it
- C below \(x\)-axis at a distance \(\frac{3}{2}\) from it
- D below x -axis at a distance \(\frac{2}{3}\) from it
Answer & Solution
Correct Answer
(C) below \(x\)-axis at a distance \(\frac{3}{2}\) from it
Step-by-step Solution
Detailed explanation
Let the line be \((a x+2 b y+3 b)+\lambda(b x-2 a y-3 a)=0\) \(\because\) It is parallel to \(x\)-axis. \(\therefore \frac{\mathrm{a}+\mathrm{b} \lambda}{2 \mathrm{a} \lambda-2 \mathrm{~b}}=0 \Rightarrow \lambda=-\frac{\mathrm{a}}{\mathrm{~b}}\) So, equation is…
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