WBJEE · Maths · Functions
The range of the function \(y=3 \sin \left(\sqrt{\frac{\pi^{2}}{16}-x^{2}}\right)\) is
- A \([0, \sqrt{3 / 2}]\)
- B [0,1]
- C \([0,3 / \sqrt{2}]\)
- D \([0, \infty)\)
Answer & Solution
Correct Answer
(C) \([0,3 / \sqrt{2}]\)
Step-by-step Solution
Detailed explanation
Given function is \(y=3 \sin \left(\sqrt{\frac{\pi^{2}}{16}-x^{2}}\right)\) Here, domain is \(\left[0, \frac{\pi}{4}\right]\)…
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