WBJEE · Maths · Hyperbola
Let \(A(2 \sec \theta, 3 \tan \theta)\) and \(B(2 \sec \phi, 3 \tan \phi)\) where \(\theta+\phi=\frac{\pi}{2}\) be two points on the hyperbola \(\frac{x^2}{4}-\frac{y^2}{9}=1\). If \((\alpha, \beta)\) is the point of intersection of normals to the hyperbola at \(A\) and \(B\), then \(\beta\) is equal to
- A \(\frac{12}{3}\)
- B \(\frac{13}{3}\)
- C \(-\frac{12}{3}\)
- D \(-\frac{13}{3}\)
Answer & Solution
Correct Answer
(D) \(-\frac{13}{3}\)
Step-by-step Solution
Detailed explanation
Hint : Equation of Normal at \(A\) \(\frac{4 x}{2 \sec \theta}+\frac{9 y}{3 \tan \theta}=13\) at \(B\)…
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