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WBJEE · Maths · Circle

The equations of the circles, which touch both the axes and the line \(4 x+3 y=12\) and have centres in the first quadrant, are

  1. A \(x^{2}+y^{2}+x-y+1=0\)
  2. B \(x^{2}+y^{2}-2 x-2 y+1=0\)
  3. C \(x^{2}+y^{2}-12 x-12 y+36=0\)
  4. D \(x^{2}+y^{2}-6 x-6 y+36=0\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(x^{2}+y^{2}-12 x-12 y+36=0\)

Step-by-step Solution

Detailed explanation

Radius \((r)=\) perpendicular distance on line \(4 x+3 y=12\) from centre \(\Rightarrow \quad r=\frac{|4 r+3 r-12|}{\sqrt{16+9}}\) \(\Rightarrow \quad|7 r-12|=5 r\) \(\Rightarrow \quad 7 r-12=\pm 5 r\) \(\therefore \quad 2 r=12 \Rightarrow r=6\) and \(12 r=12 \Rightarrow r=1\)…