WBJEE · Maths · Functions
A Mapping from IN to IN is defined as follows :
\[
\begin{aligned}
& \mathrm{f}: \mathrm{IN} \rightarrow \mathrm{IN} \\
& \mathrm{f}(\mathrm{n})=(\mathrm{n}+5)^2, \mathrm{n} \in \mathrm{IN}
\end{aligned}
\]
(IN is the set of natural numbers). Then
- A \(\mathrm{f}\) is not one-to-one
- B \(\mathrm{f}\) is onto
- C \(\mathrm{f}\) is both one-to-one and onto
- D \(\mathrm{f}\) is one-to-one but not onto
Answer & Solution
Correct Answer
(D) \(\mathrm{f}\) is one-to-one but not onto
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Hints: } \mathrm{f}: \mathrm{IN} \rightarrow \mathrm{IN} ; \mathrm{f}(\mathrm{n})=(\mathrm{n}+5)^2 \\ & \left(\mathrm{n}_1+5\right)^2=\left(\mathrm{n}_2+5\right)^2 \\ &…
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