WBJEE · Maths · Circle
The equation of the circle passing through the point (1,1) and the points of intersection of \(x^{2}+y^{2}-6 x-8=0\) and \(x^{2}+y^{2}-6=0\) is
- A \(x^{2}+y^{2}+3 x-5=0\)
- B \(x^{2}+y^{2}-4 x+2=0\)
- C \(x^{2}+y^{2}+6 x-4=0\)
- D \(x^{2}+y^{2}-4 y-2=0\)
Answer & Solution
Correct Answer
(A) \(x^{2}+y^{2}+3 x-5=0\)
Step-by-step Solution
Detailed explanation
Let \(\quad S_{1}=x^{2}+y^{2}-6 x-8=0\) and \(\quad S_{2}=x^{2}+y^{2}-6=0\) Now, the equation of the circle passing through the point (1,1) and the point of intersection of \(S_{1}\) and \(S_{2}\) is \[ S_{1}+\lambda S_{2}=0 \]…
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