WBJEE · Maths · Circle
The equation of a line parallel to the line \(3 x+4 y=0\) and touching the circle \(x^{2}+y^{2}=9\) in the first quadrant, is
- A \(3 x+4 y=15\)
- B \(3 x+4 y=45\)
- C \(3 x+4 y=9\)
- D \(3 x+4 y=27\)
Answer & Solution
Correct Answer
(A) \(3 x+4 y=15\)
Step-by-step Solution
Detailed explanation
Equation of circle is \(x^{2}+y^{2}=9\) ...(i) And equation of line is \(3 x+4 y=0\) ....(ii) Equation of line parallel to the line (ii) . \(=\) \[ \begin{aligned} 3 x+4 y &=k \\ y &=\frac{-3 x}{4}+\frac{k}{4} ...(iii) \end{aligned} \] \(\because\) Circle touches the line (iii),…
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