WBJEE · Maths · Quadratic Equation
If \(p, q\) are the roots of the equation \(x^{2}+p x+q=0,\) then
- A \(p=1, q=-2\)
- B \(p=0, q=1\)
- C \(p=-2, q=0\)
- D \(p=-2, q=1\)
Answer & Solution
Correct Answer
(A) \(p=1, q=-2\)
Step-by-step Solution
Detailed explanation
Given, \(\rho, q\) are roots of equation \(x^{2}+p x+q=0\) \(\therefore \quad p+q=-p \Rightarrow 2 p+q=0\) \(\begin{array}{lr}\text { and } & p q=q \\ \Rightarrow & \rho=1\end{array}\) Put \(p=1\) in Eq, we get \(2 \times 1+q=0\)…
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