WBJEE · Maths · Probability
In a certain town, \(60 \%\) of the families own a car, \(30 \%\) own a house and \(20 \%\) own both car and house. If a family is randomly chosen. then what is the probability that this family owns a car or a house but not both?
- A 0.5
- B 0.7
- C 0.1
- D 0.9
Answer & Solution
Correct Answer
(A) 0.5
Step-by-step Solution
Detailed explanation
Let \(A\) be the set of families who own a car and \(B\) be the set of families who own a house. Then, \(\quad P(A)=60 \%, P(B)=30 \%\) and \(P(A \cap B)=20 \%\) Now, \(P(A \cup B)=P(A)+P(B)-P(A \cap B)\) \(=60+30-20=70 \%\) Now, families who owns a car or a house but not both…
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