WBJEE · Maths · Straight Lines
The coordinates of a point on the line \(x+y+1=0,\) which is at a distance \(\frac{1}{5}\) unit from the line \(3 x+4 y+2=0,\) are
- A (2,-3)
- B (-3,2)
- C (0,-1)
- D (-1,0)
Answer & Solution
Correct Answer
(D) (-1,0)
Step-by-step Solution
Detailed explanation
Let \((h, k)\) be the point on line \(x+y+1=0\) So. \[ h+k+1=0 \] \[ h=-1-k \] Given, distance between \((h, k)\) and line \(3 x+4 y+2=0\) is \(\frac{1}{5}\) \(\therefore\) \(\frac{1}{5}=\left|\frac{(3 h)+(4 k)+2}{\sqrt{3^{2}+4^{2}}}\right|\)…
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