WBJEE · Maths · Probability
If 5 distinct balls are placed at random into 5 cells, then the probability that exactly one cell remains empty, is
- A \(48 / 125\)
- B \(12 / 125\)
- C \(8 / 125\)
- D \(1 / 125\)
Answer & Solution
Correct Answer
(A) \(48 / 125\)
Step-by-step Solution
Detailed explanation
Clearly. 5 distinct balls can be placed into 5 olls in \(5^{5}\) ways. Now, the number of ways of selecting one cell \({ }^{5} C_{1}\) Let the selected cell be empty, Now, we are left with 5 balls and 4 cells. Now, number of ways of placing 5 distinct balls into 4 cells such…
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