WBJEE · Maths · Ellipse
The co-ordinate of a point on the auxiliary circle of the ellipse \(x^{2}+2 y^{2}=4\) corresponding to the point on the ellipse whose eccentric angle is \(60^{\circ}\) will be
- A \((\sqrt{3}, 1)\)
- B \((1, \sqrt{3})\)
- C \((1,1)\)
- D \((1,2)\)
Answer & Solution
Correct Answer
(B) \((1, \sqrt{3})\)
Step-by-step Solution
Detailed explanation
\(\frac{x^{2}}{4}+\frac{y^{2}}{2}=1\) Equation of auxiliary circle is \(x^{2}+y^{2}=4\) \(\therefore\) Point on the auxiliary circle is \(\begin{array}{l} p\left(2 \cos 60^{\circ}, 2 \sin 60^{\circ}\right) \\ p(1, \sqrt{3}) \end{array}\)
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