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WBJEE · Maths · Quadratic Equation

Let \(\alpha, \beta\) be the roots of \(x^{2}-x-1=0\) and \(S_{n}=\alpha^{n}+\beta^{n},\) for all integers \(n \geq 1 .\) Then, for every integer \(n \geq 2\)

  1. A \(S_{n}+S_{n-1}=S_{n+1}\)
  2. B \(S_{n}-S_{n-1}=S_{n+1}\)
  3. C \(S_{n-1}=S_{n+1}\)
  4. D \(S_{n}+S_{n-1}=2 S_{n+1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(S_{n}+S_{n-1}=S_{n+1}\)

Step-by-step Solution

Detailed explanation

Given, \(\alpha\) and \(\beta\) are the roots of \(x^{2}-x-1=0\) \(\therefore \quad \alpha+\beta=1\) and \(\alpha \beta=-1\) Now, consider option (a). \(S_{n}+S_{n-1}=S_{n+1}\) Put \(n=2\), we get, \(\quad S_{2}+S_{1}=S_{3}\)…