WBJEE · Physics · Motion In Two Dimensions
A ball is projected horizontally with a velocity of \(5 \mathrm{~m} / \mathrm{s}\) from the top of a building \(19.6 \mathrm{~m}\) high. How long will the ball take of hit the ground?
- A \(\sqrt{2} \mathrm{~s}\)
- B \(2 \mathrm{~s}\)
- C \(\sqrt{3} \mathrm{~s}\)
- D \(3 \mathrm{~s}\)
Answer & Solution
Correct Answer
(B) \(2 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
Hints: \(\mathrm{T}=\sqrt{\frac{2 \mathrm{H}}{g}}=\sqrt{\frac{2 \times 19.6}{9.8}}=2 \mathrm{sec}\)
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