WBJEE · Maths · Circle
The angle between a pair of tangents drawn from a point \(P\) to the circle
\(x^{2}+y^{2}+4 x-6 y+9 \sin ^{2} \alpha+\)
\(13 \cos ^{2} \alpha=0\) is \(2 \alpha .\) The equation of the locus of the point \(P\) is
- A \(x^{2}+y^{2}+4 x+6 y+9=0\)
- B \(x^{2}+y^{2}-4 x+6 y+9=0\)
- C \(x^{2}+y^{2}-4 x-6 y+9=0\)
- D \(x^{2}+y^{2}+4 x-6 y+9=0\)
Answer & Solution
Correct Answer
(D) \(x^{2}+y^{2}+4 x-6 y+9=0\)
Step-by-step Solution
Detailed explanation
We have equation of circle \(x^{2}+y^{2}+4 x-6 y+9 \sin ^{2} \alpha+13 \cos ^{2} \alpha=0\) Here,…
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