WBJEE · Maths · Properties of Triangles
Let \(p, q\) and \(r\) be the side4s opposite to the angles \(P, Q\) and \(R,\) respectively in a \(\Delta P Q R\). Then, \(2 p r \sin \left(\frac{p-Q+R}{2}\right)\) equals
- A \(p^{2}+q^{2}+r^{2}\)
- B \(p^{2}+r^{2}-q^{2}\)
- C \(q^{2}+r^{2}-p^{2}\)
- D \(p^{2}+q^{2}-r^{2}\)
Answer & Solution
Correct Answer
(B) \(p^{2}+r^{2}-q^{2}\)
Step-by-step Solution
Detailed explanation
In \(\Delta P Q R, P+Q+R=180^{\circ}\)…
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