WBJEE · Maths · Vector Algebra
Let \(\vec{\alpha}=\hat{i}+\hat{j}+\hat{k}, \vec{\beta}=\hat{i}-\hat{j}-\hat{k}\) and
\(\vec{\gamma}=-\hat{i}+\hat{j}-\hat{k}\) be three vectors. A vector \(\vec{\delta},\) in the plane of \(\vec{\alpha}\) and \(\vec{\beta}\), whose projection on \(\vec{\gamma}\) is \(\frac{1}{\sqrt{3}},\) is given by
- A \(-\hat{i}-3 \hat{j}-3 \hat{k}\)
- B \(\hat{i}-3 \hat{j}-3 \hat{k}\)
- C \(-\hat{i}+3 \hat{j}+3 \hat{k}\)
- D \(\hat{i}+3 \hat{j}-3 \hat{k}\)
Answer & Solution
Correct Answer
(C) \(-\hat{i}+3 \hat{j}+3 \hat{k}\)
Step-by-step Solution
Detailed explanation
We have, \(\overrightarrow{8}=\vec{a}+\lambda \vec{\beta}\) \(=(\hat{i}+\hat{j}+\hat{k})+\lambda(\hat{i}-\hat{j}-\hat{k})\) \(\Rightarrow \quad \vec{\delta}=(1+\lambda) \hat{i}+(1-\lambda) \hat{j}+(1-\lambda) \hat{k}\) Given,…
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