WBJEE · Physics · Mechanical Properties of Fluids
A drop of water detaches itself from the exit of a tap when \((\sigma=\) surface tension of water, \(\rho=\) density of water, \(R=\) radius of the tap exit, \(r=\) radius of the drop \()\)
- A \(r>\left(\frac{2}{3} \frac{R \sigma}{\rho g}\right)^{1 / 3}\)
- B \(r=\frac{2}{3} \frac{\sigma}{\rho g}\)
- C \(\frac{2 \sigma}{r}>\) atmospheric pressure
- D None of the above
Answer & Solution
Correct Answer
(D) None of the above
Step-by-step Solution
Detailed explanation
Let mass of the drop \(=m\) Weight of the drop = mg It will act downward. The force due to surface tension on the drop \(=\sigma2 \pi R\) Where, \(R=\) radius of tap If will act in upward direction. The drop of water will detach when \[ m g>\sigma 2 \pi R \]…
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