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WBJEE · Maths · Permutation Combination

Let \(A\) be a set containing \(n\) elements. \(A\) subset \(P\) of \(A\) is chosen, and the set \(A\) is reconstructed by replacing the elements of \(P\). A subset \(Q\) of \(A\) is chosen again. The number of ways of choosing \(P\) and \(Q\) such the \(Q\) contains just one element more than \(P\) is

  1. A \({ }^{2 n} C_{n-1}\)
  2. B \({ }^{2 n} C_n\)
  3. C \({ }^{2 n} C_{n+2}\)
  4. D \(2^{2 n+1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \({ }^{2 n} C_{n-1}\)

Step-by-step Solution

Detailed explanation

Hint : Required number of ways…