WBJEE · Maths · Differential Equations
The curve \(y=(\cos x+y)^{1 / 2}\) satisfies the differential equation
- A \((2 y-1) \frac{d^{2} y}{d x^{2}}+2\left(\frac{d y}{d x}\right)^{2}+\cos x=0\)
- B \(\frac{d^{2} y}{d x^{2}}-2 y\left(\frac{d y}{d x}\right)^{2}+\cos x=0\)
- C \((2 y-1) \frac{d^{2} y}{d x^{2}}-2\left(\frac{d y}{d x}\right)^{2}+\cos x=0\)
- D \((2 y-1) \frac{d^{2} y}{d x^{2}}-\left(\frac{d y}{d x}\right)^{2}+\cos x=0\)
Answer & Solution
Correct Answer
(A) \((2 y-1) \frac{d^{2} y}{d x^{2}}+2\left(\frac{d y}{d x}\right)^{2}+\cos x=0\)
Step-by-step Solution
Detailed explanation
Given curve is \[ y=(\cos x+y)^{1 / 2} \] On differentiating both sides w.r.t. \(x,\) we get…
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