WBJEE · Maths · Vector Algebra
The unit vector in ZOX plane, making angles \(45^{\circ}\) and \(60^{\circ}\) respectively with \(\vec{\alpha}=2 \hat{i}+2 \hat{j}-\hat{k}\) and \(\vec{\beta}=j-\hat{k}\) is
- A \(\frac{1}{\sqrt{2}} \hat{i}+\frac{1}{\sqrt{2}} \hat{j}\)
- B \(\frac{1}{\sqrt{2}} \hat{\mathrm{i}}-\frac{1}{\sqrt{2}} \hat{\mathrm{k}}\)
- C \(\frac{1}{\sqrt{2}} \hat{i}-\frac{1}{\sqrt{2}} \hat{j}\)
- D \(\frac{1}{\sqrt{2}} \hat{i}+\frac{1}{\sqrt{2}} \hat{k}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{\sqrt{2}} \hat{\mathrm{i}}-\frac{1}{\sqrt{2}} \hat{\mathrm{k}}\)
Step-by-step Solution
Detailed explanation
Hint: Let the vector be \(\vec{r}=x \hat{i}+z \hat{k} \Rightarrow|r|=1\) \(\vec{r} \cdot \vec{a}=|r| |\vec{\alpha}| \cos 45^{\circ}\) \(\therefore 2 x-z=\frac{3}{\sqrt{2}}\) \(\vec{r} \cdot \vec{\beta}=|\vec{r}| |\vec{\beta}| \cos 60^{\circ}\) \(z=-\frac{1}{\sqrt{2}}\)…
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