WBJEE · Maths · Probability
Three numbers are chosen at random without replacement from \(\{1,2, \ldots .10\}\). The probability that the minimum of the chosen numbers is 3 or their maximum is 7 , is
- A \(\frac{5}{40}\)
- B \(\frac{3}{40}\)
- C \(\frac{11}{40}\)
- D \(\frac{9}{40}\)
Answer & Solution
Correct Answer
(C) \(\frac{11}{40}\)
Step-by-step Solution
Detailed explanation
\(\frac{{ }^7 \mathrm{C}_2+{ }^6 \mathrm{C}_2-{ }^3 \mathrm{C}_1}{{ }^{10} \mathrm{C}_3}=\frac{33}{120}=\frac{11}{40}\)
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