WBJEE · Maths · Properties of Triangles
In a triangle \(\mathrm{ABC}\) if \(\sin \mathrm{A} \sin \mathrm{B}=\frac{\mathrm{ab}}{\mathrm{c}^2}\), then the triangle is
- A equilateral
- B isosceles
- C right angled
- D obtuse angled
Answer & Solution
Correct Answer
(C) right angled
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Hints }: \sin A \sin B=\frac{a b}{c^2} \\ & \Rightarrow c^2=\frac{a b}{\sin A \sin B}=\left(\frac{a}{\sin A}\right)\left(\frac{b}{\sin B}\right) \\ & \Rightarrow c^2=\left(\frac{c}{\sin C}\right)^2 \Rightarrow \sin ^2 C=1 \Rightarrow \sin C=1…
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