WBJEE · Maths · Properties of Triangles
In \(\Delta A B C\), if \(a^{2} \cos ^{2} A-b^{2}-c^{2}=0,\) then
- A \(\frac{\pi}{4} < A < \frac{\pi}{2}\)
- B \(\frac{\pi}{2} < A < \pi\)
- C \(A=\frac{\pi}{2}\)
- D \(A < \frac{\pi}{4}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{2} < A < \pi\)
Step-by-step Solution
Detailed explanation
We have, \(a^{2} \cos ^{2} A-b^{2}-c^{2}=0\) \(\Rightarrow \quad a^{2} \cos ^{2} A=b^{2}+c^{2}\) Also in \(\triangle A B C\), we have…
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