WBJEE · Maths · Straight Lines
If \(P(0,0), Q(1,0)\) and \(R\left(\frac{1}{2}, \frac{\sqrt{3}}{2}\right)\) are three given points, then the centre of the circle for which the lines \(P Q, Q R\) and \(R P\) are the tangents is
- A \(\left(\frac{1}{2}, \frac{1}{4}\right)\)
- B \(\left(\frac{1}{2}, \frac{\sqrt{3}}{4}\right)\)
- C \(\left(\frac{1}{2}, \frac{1}{2 \sqrt{3}}\right)\)
- D \(\left(\frac{1}{2}, \frac{-1}{\sqrt{3}}\right)\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{1}{2}, \frac{1}{2 \sqrt{3}}\right)\)
Step-by-step Solution
Detailed explanation
\begin{aligned} &\text { } I=\left(\frac{a x_{1}+b x_{2}+c x_{3}}{a+b+c}, \frac{a y_{1}+b y_{2}+c y_{3}}{a+b+c}\right)\\ &a=\sqrt{\frac{1}{4}+\frac{3}{4}}=1, b=1, c=1\\ &\text { Centre of the circle. }\\ &=\left(\frac{1 \times 0+1 \times 1+1 \times \frac{1}{2}}{1+1+1}, \frac{1…
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