WBJEE · Chemistry · Structure of Atom
Which hydrogen like species will have the same radius as that of \(1^{\text {st }}\) Bohr orbit of hydrogen atom?
- A \(\mathrm{n}=2, \mathrm{Li}^{2+}\)
- B \(\mathrm{n}=2, \mathrm{Be}^{3+}\)
- C \(\mathrm{n}=2, \mathrm{He}^{+}\)
- D \(\mathrm{n}=3, \mathrm{Li}^{2+}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{n}=2, \mathrm{Be}^{3+}\)
Step-by-step Solution
Detailed explanation
Hint : Radius of \(n^{\text {th }}\) orbit \(=0.529 \frac{n^2}{Z} Ã…\) Radius of \(1^{\text {st }}\) Bohr Orbit of Hydrogen atom \(=0.529 \times \frac{1^2}{1}=0.529 Ã…\) Radius of \(2^{\text {nd }}\) Bohr Orbit of \(\mathrm{Be}^{3+}=0.529 \frac{2^2}{4}=0.529 Ã…\)
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