WBJEE · Maths · Probability
Two smallest squares are chosen one by one on a chess board. The probability that they have a side in common is
- A \(\frac{1}{9}\)
- B \(\frac{2}{7}\)
- C \(\frac{1}{18}\)
- D \(\frac{5}{18}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{18}\)
Step-by-step Solution
Detailed explanation
Out of 64 squares, two squares are selected in 64C2 ways= \(64 \times 63\) Hint :…
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