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WBJEE · Maths · Complex Number

If \(\cos \theta+i \sin \theta, \theta \in \mathbb{R}\), is the root of the equation
\(a_0 x^n+a_1 \cdot x^{n-1}+\ldots .+a_{n-1} x+a_n=0, a_0, a_1, \ldots \ldots . a_n \in \mathbb{R}, a_0 \neq 0\)
then the value of \(a_1 \sin \theta+a_2 \sin 2 \theta+\ldots .+a_n \sin n \theta\) is

  1. A 2n
  2. B n
  3. C 0
  4. D n+1
Verified Solution

Answer & Solution

Correct Answer

(C) 0

Step-by-step Solution

Detailed explanation

Hint: \(a_0 x^n+a_1 \cdot x^{n-1}+\ldots .+a_{n-1} x+a_n=0\) divided by \(x^n\) \(a_0+a_1 \frac{1}{x}+\ldots \ldots+a_{n-1} \frac{1}{x^{n-1}}+a_n \frac{1}{x^n}=0\) put \(x=\cos \theta+i \sin \theta\) and equating imaginary part…
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