WBJEE · Maths · Limits
Let \(x_{n}=\left(1-\frac{1}{3}\right)^{2}\left(1-\frac{1}{6}\right)^{2}\left(1-\frac{1}{10}\right)^{2} \ldots\) \(\left(1-\frac{1}{\frac{n(n+1)}{2}}\right)^{2}, n \geq 2\) Then, the value of \(\lim _{n \rightarrow \infty} x_{n}\) is
- A \(1 / 3\)
- B \(1 / 9\)
- C \(1 / 81\)
- D 0
Answer & Solution
Correct Answer
(B) \(1 / 9\)
Step-by-step Solution
Detailed explanation
We have, \(x_{n}=\left[\left(1-\frac{1}{3}\right)\left(1-\frac{1}{6}\right)\right.\) \[ \left.\left(1-\frac{1}{10}\right) \ldots\left(1-\frac{2}{n(n+1)}\right)\right]^{2} \]…
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