WBJEE · Maths · Application of Derivatives
Consider the curve \(y=\) be \(^{-\frac{x}{ \text { a }}}\) where \(a\) and \(b\) are non-zero real numbers. Then
- A \(\frac{x}{a}+\frac{y}{b}=1\) is tangent to the curve at \((0,0)\)
- B \(\frac{x}{a}+\frac{y}{b}=1\) is tangent to the curve where the curve crosses the axis of \(y\)
- C \(\frac{x}{a}+\frac{Y}{b}=1\) is tangent to the curve at \((a, 0)\)
- D \(\frac{x}{a}+\frac{y}{b}=1\) is tangent to the curve at \((2 a, 0)\)
Answer & Solution
Correct Answer
(B) \(\frac{x}{a}+\frac{y}{b}=1\) is tangent to the curve where the curve crosses the axis of \(y\)
Step-by-step Solution
Detailed explanation
Hint: \(y-b=-\frac{b}{a}(x) \Rightarrow \frac{x}{a}+\frac{y}{b}=1\)
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