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WBJEE · Maths · Quadratic Equation

If \(\alpha\) and \(\beta\) are the roots of \(x^{2}-p x+1=0\) and \(\gamma\) is a root of \(x^{2}+p x+1=0,\) then \((\alpha+\gamma)(\beta+\gamma)\) is

  1. A 0
  2. B 1
  3. C -1
  4. D \(p\)
Verified Solution

Answer & Solution

Correct Answer

(A) 0

Step-by-step Solution

Detailed explanation

Since, \(\alpha\) and \(\beta\) are the roots of \(x^{2}-p x+1=0\). \(\therefore\) \(\alpha+\beta=p\) and \(\alpha \beta=1\) Also, \(\gamma\) is the root of \(x^{2}+p x+1=0\) \(\therefore \quad \gamma^{2}+p{\gamma}+1=0 \Rightarrow \gamma^{2}=-p \gamma-1\) Now,…