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WBJEE · Maths · Sequences and Series

If 64,27,36 are the Pth \(Q\) th and \(R\) th terms of a GP, then \(P+2 Q\) is equal to

  1. A \(R\)
  2. B \(2 R\)
  3. C \(3 R\)
  4. D \(4 R\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(3 R\)

Step-by-step Solution

Detailed explanation

Let a be the first term and \(r\) be the common ration of a GP. \(\therefore P^{\text {th }}, Q^{\text {th }}\) and \(R^{\text {th }}\) terms of a GP are respectively ar \({ }^{\mathrm{P}-1}\), ar \(\mathrm{Q}^{-1}\) and \({a r}^{\mathrm{R}-1}\). According to question,…