WBJEE · Maths · Determinants
Let \(a, b, c\) be such that \(b(a+c) \times 0\)
If \(\left|\begin{array}{ccc}a & a+1 & a-1 \\ -b & b+1 & b-1 \\ c & c-1 & c+1\end{array}\right|\)
\(+\left|\begin{array}{ccc}a+1 & b+1 & c-1 \\ a-1 & b-1 & c+1 \\ (-1)^{n+2} a & (-1)^{n+1} b & (-1)^{n} c\end{array}\right|=0\)
then the value of \(n\) is
- A any integer
- B zero
- C any even integer
- D any odd integer
Answer & Solution
Correct Answer
(D) any odd integer
Step-by-step Solution
Detailed explanation
We have, \(\left|\begin{array}{ccc}a & a+1 & a-1 \\ -b & b+1 & b-1 \\ c & c-1 & c+1\end{array}\right|\) + \(\left|\begin{array}{ccc}a+1 & b+1 & c-1 \\ a-1 & b-1 & c+1 \\ (-1)^{n+2} a & (-1)^{n+1} b & (-1)^{n} c\end{array}\right|=0\)…
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