WBJEE · Maths · Basic of Mathematics
The number of digits in \(20^{301}\) (given, \(\log _{10} 2=0.3010\) is
- A 602
- B 301
- C 392
- D 391
Answer & Solution
Correct Answer
(C) 392
Step-by-step Solution
Detailed explanation
Let \(y=20^{301}\) Number of digits \(=\) Integral part of \(\left(301 \log _{10} 20\right)+1\) Integral part of \(\left.\left[301 \log _{10} 10+\log _{10} 2\right)\right]+1\) \(=\) Integral part of \([301(1+0.3010)]+1\) \(=\) Integral part of \([301 \times 1.3010]+1\) Integral…
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