WBJEE · Maths · Basic of Mathematics
Given that, \(x\) is a real number satisfying \(\frac{5 x^{2}-26 x+5}{3 x^{2}-10 x+3} < 0,\) then
- A \(x < \frac{1}{5}\)
- B \(\frac{1}{5} < x < 3\)
- C \(x>5\)
- D \(\frac{1}{5} < x < \frac{1}{3}\) or \(3 < x < 5\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{5} < x < \frac{1}{3}\) or \(3 < x < 5\)
Step-by-step Solution
Detailed explanation
We have, \(\frac{5 x^{2}-26 x+5}{3 x^{2}-10 x+3} < 0\) \(\Rightarrow \quad \frac{5 x^{2}-25 x-x+5}{3 x^{2}-9 x-x+3} < 0\) \(\Rightarrow \quad \frac{5 x(x-5)-1(x-5)}{3 x(x-3)-1(x-3)} < 0 \Rightarrow \frac{(x-5)(5 x-1)}{(x-3)(3 x-1)} < 0\)…
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