WBJEE · Maths · Application of Derivatives
A curve passes through the point \((3,2)\) for which the segment of the tangent line contained between the co-ordinate axes is bisected at the point of contact. The equation of the curve is
- A \(y=x^2-7\)
- B \(x=\frac{y^2}{2}+2\)
- C \(x y=6\)
- D \(x^2+y^2-5 x+7 y+11=0\)
Answer & Solution
Correct Answer
(C) \(x y=6\)
Step-by-step Solution
Detailed explanation
\(\frac{x}{x_1}+\frac{y}{y_1}=2\) \(\because\left(\frac{d y}{d x}\right)_{\left(x_1, y_1\right)}=-\frac{y_1}{x_1}\)…
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